class interval freq midpoint(xi) 10-12 2 11 13-15 5 14 16-18 3 17 19-21 2 20 22-24 6 23 25-27 2 26We calculate the variance: xi xi-mu (xi-mu)^2 fi(xi-mu)^2 ----------------------------------------------------------- 11 -7.65 58.5225 2(58.5225) = 117.045 14 -4.65 21.6225 5(21.6225) = 108.1125 17 -1.65 2.7225 3(2.7225) = 8.1675 20 1.35 1.9225 2(1.8225) = 3.645 23 4.35 18.9225 6(18.9225) = 113.535 26 7.35 54.0225 2(54.0225) = 108.045 ----------------------------------------------------------- 458.65 (c) 2 were in 10-12 and 5 were in 13-15, so 2+5=7 failed P(failure) = 7/20 = 0.35 Edwin