SOLUTION: [x/(x-1)]^(1/x) = (x-1)^(x-2), find x.

Algebra.Com
Question 1209501: [x/(x-1)]^(1/x) = (x-1)^(x-2),
find x.

Answer by mccravyedwin(408)   (Show Source): You can put this solution on YOUR website!

There is no algebraic way to handle this.
I'd just use a TI-84 calculator and approximate it.
You can use logs, but it doesn't help.  When unknowns
appear both in and out of exponents or special functions,
then algebra is useless.

x ≈ 2.501721792

Edwin

RELATED QUESTIONS

x+1=2 find... (answered by longjonsilver)
x+1=2 find... (answered by Prithwis)
x+(x-1)<(x+2)-(x+1) (answered by jim_thompson5910)
x/x = 2 -... (answered by mukhopadhyay)
((x)/(x+1))/((1)/(x^2-1) -... (answered by jim_thompson5910)
|x|+|x+2|>=... (answered by persian52)
(x+1)/x >... (answered by Fombitz)
x=2.... (answered by Tatiana_Stebko)
(X-2)(x+1) (answered by oscargut)
If x^x=2, calculate x^x^x+1 +... (answered by ikleyn)