SOLUTION: Simplify [1/(tanx + cotx + secx + cosecx)]²

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Question 1208297: Simplify
[1/(tanx + cotx + secx + cosecx)]²

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!

 



Draw a right triangle with angle x, hypotenuse 1, and legs "a" and "b"


 


Since , that's
because by the Pythagorean theorem, a2+b2=1



Multiply top and bottom by a2b2



We multiply out the denominator,



Since a2+b2=1,





The denominator factors



Multiply by the product of the "conjugates" of the
factors on the bottom over itself. (Sort of like
rationalizing the denominator)




 


By the Pythagorean theorem  1-a2=b2 and 1-b2=a2



Canceling:



Since a = sin(x) and b = cos(x)

  <--simplest form

Edwin

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