SOLUTION: If sin3y = cos2y and 0°≤y≤90°, find the values of y.

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Question 1207451: If sin3y = cos2y and 0°≤y≤90°, find the values of y.
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
sin(3y)=cos(2y),   




For the case 



which simplifies to




This gives us the solutions 18o, 90o, for n=0 and n=1

However, this may not be all possible solutions 

We must also consider the case



which simplifies to




We get only a repeat of the solution 90o for n=0 

18o, 90o are the only solutions 

Edwin
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