SOLUTION: Find the formula of the sequences in terms of n and Tn 1) 24,12,6,3... 2) 0,-1/2,-1,-3/2...

Question 1204841: Find the formula of the sequences in terms of n and Tn
1) 24,12,6,3...
2) 0,-1/2,-1,-3/2...
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
General formula for Tn the nth term in an geometric progression is

where a is the first term and is the common ratio and is the number of terms
1) 24,12,6,3...
24,12,6,3... the common ratio is 12/24 =6/12 = 6/12 =1/2
a= 24

2) 0,-1/2,-1,-3/2...
0,-1/2,-1,-3/2...
-1/2-0 = -1-(-1/2) = (-3/2)-(-1)= -1/2
The difference between two consecutive terms is -1/2 = d
The nth. term of an AP is
, a is first term and n the number of terms
a=0 , and d= -1/2

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