P can complete a task in x days while Q takes (x + 12) days to do the same task.
a) What fraction of the task can each of them complete in a day?
P can complete 1 task in x days, so P can complete 1/x of a task in 1 day.
Q can complete 1 task in (x + 12) days, so Q can complete 1/(x + 12) of a task
in 1 day.
b) If both of them work together, they can
complete the task in 8 days. Find x.
P can complete 1/x of a task in 1 day, so P can complete 8/x of a task in 8
days.
Q can complete 1/(x + 12) of a task in 1 day, so Q can complete 8/(x + 12) of a
task in 8 days.
So together, they can complete 8/x + 8/(x+12) of a task in 8 days
That's 1 task, so
LCD = x(x + 12)
x+8=0; x-12=0
x=-8; x=12
x cannot be negative.
x = 12.
Now that we have x, we can answer (a) as a numerical fraction:
a) What fraction of the task can each of them complete in a day?
P can complete 1 task in 12 days, so P can complete 1/12 of a task in 1 day.
Q can complete 1 task in (12 + 12) = 24 days, so Q can complete 1/(12 + 12) = 1/24 of a task in 1 day.
Edwin