SOLUTION: The points are (10,-2) find new points after the tranformation y = -3f(1/4(x-1)) + 5

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Question 1203642: The points are (10,-2) find new points after the tranformation y = -3f(1/4(x-1)) + 5
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!


 

This is multiplying the variable x only by a number < 1 which stretches the
graph horizontally by a factor of 4, which stretches the point (10,-2)
horizontally to (40,-2).

 

This is subtracting 1 from the variable x only by 1 which shifts the graph 
horizontally 1 unit right, which shifts the point (40,-2) to (40,-1).

 

This is multiplying the entire function by 3 which stretches the graph
vertically by a factor of 3 and stretches the point (40,-1) to (40,-3)

 

This is multiplying the entire function by -1 which reflects the graph
vertically across the x-axis, which moves the point (40,-3) vertically across
the x-axis to (40,3).

 

This is adding 5 to the entire function which shifts the graph vertically upward
by 5 units, which moves the point (40,3) vertically upward to (40,8).

Edwin
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

Your post is DEFECTIVE, since the function f is not defined in the post.

Also, the grammar is incorrect, since you use the plural form "the points are",
while there is only one point under consideration.



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