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A steel ball falls from rest through a height of 2.10 meters .
An electronic timer records a time of 0.67 seconds for the fall.
c) Calculate the average acceleration of the ball as it falls.
d) Suggest reasons why the answer is not exactly 9.81 ms^-2
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Use the standard formula "the height - the time" for the uniformly accelerated move
h = ,
where "a" is the average acceleration.
In your case it is
2.10 = .
It gives
a = = 9.36 m/s^2.
It is the answer to question (c).
The normal/ordinary value for the gravity acceleration at the Earth surface is 9.81 m/s^2.
The reason for the difference usually is due to the air resistance.
Solved.