SOLUTION: The bases of a right cylindrical solid are each 135 degrees sectors of circles with a 4-inch radius each. The altitude of the solid is 12 inches. The the total surface area of thi
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Question 1197280: The bases of a right cylindrical solid are each 135 degrees sectors of circles with a 4-inch radius each. The altitude of the solid is 12 inches. The the total surface area of this solid may be expressed as T = d(pi + k) square inches. Find d + k.
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Not clear.
Is there a drawing?
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
I think the description is sufficiently clear. I see a tall cylindrical cake, originally with a radius of 4 inches and a height of 12 inches, from which several slices have been removed, leaving bases that are 135-degree sectors of the original circular bases. The surfaces of the "cake" are these:
(1) 2 bases that are 135-degree sectors of circles with radius 4;
(2) the curved lateral surfaces of the cake; and
(3) 2 rectangular surfaces where the cuts were made.
The areas of those surfaces are
(1)
(2)
(3)
The total surface area of the solid is
You can put that result in the prescribed form and answer the question.
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