SOLUTION: Answer the given problem, by determining the amount of products or reactant. 1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how ma

Algebra ->  Test -> SOLUTION: Answer the given problem, by determining the amount of products or reactant. 1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how ma      Log On


   



Question 1196740: Answer the given problem, by determining the amount of products or reactant.
1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be produced from 1.0 kg of limestone.
2.Nitrous oxide (N20) is also called "laughing gas". it can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H20. a.Write a balanced equation for this reaction. B. How many grams of N20 are formed if 0.46 mole of NH4N03 is used in the reaction.

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
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Answer the given problem, by determining the amount of products or reactant.
1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be produced from 1.0 kg of limestone.
2.Nitrous oxide (N20) is also called "laughing gas". it can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H20. a.Write a balanced equation for this reaction. B. How many grams of N20 are formed if 0.46 mole of NH4N03 is used in the reaction.
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Help for question #1 only:

CaCO_3, 100.0869 grams/mole
CaO, 56.0774 grams/mole

CaCO_3 ----- > CaO + CO_2

One-to-one mole relationship between the limestone and the quicklime.



%28%281000%2A56.0774%29%2F100.0869%29%2AGRAMS%2Aquicklime
Just compute this!

If you understand question #1, then you know what to do for question #2.