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A bag contains 3 black and 2 white balls.
Two balls are taken from the bag at random, without replacement.
By drawing a tree diagram, or otherwise, calculate the probability that
(a) both balls are black,
(b) at least one ball is white
(c) the two balls are the same colour.
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(a) P(both balls are black) = = = = 0.3 = 30%.
(b) P(at least one ball is white) = 1 - P(both balls are black) = = = 0.7 = 70%.
(c) P(the two balls are the same colour) = P(both are black) + P(both are white) =
= 0.3 + = 0.3 + = 0.4 = 40%.
Solved.