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A jar contains 12 red marbles numbered 1 to 12, 4 blue marbles numbered 1 to 4, and 10 white marbles numbered 1 to 10.
A marble is drawn at random from the jar. Find the probability of the given event.
Write your answers as integers or reduced fractions.
(a) The marble is red.
(b) The marble is not red.
(c) The marble has the number 2 written on it.
(d) The marble is blue with the number 1 written on it.
(e) The marble has the number 15 written on it.
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The post by @Theo has an error, so his answers are incorrect.
I came to bring a correct solution.
The total number of marbles is 12 + 4 + 10 = 26.
(a) Of the total of 26 marbles, 12 are red.
So, the probability to get randomly a red marble is = . ANSWER
(b) The probability that the marble is not red is the complement to (a), i.e.
1 - = . ANSWER
(c) There are 3 marbles of 26, having a "2" written on it,
so the probability to get such marble is . ANSWER
(d) Of the total 26 marbles, there is only one, which is blue with the number "1" written on it, so the answer is .
(e) There is no marble with "15" written on it, so the probability is 0 (zero).
Solved.