SOLUTION: In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year? (Hint: there are no ties.) Select one:

Question 1194622: In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year? (Hint: there are no ties.)
Select one:
a.
40,320

b.
362,880

c.
3,628,750

d.
181,440
Answer by ikleyn(52777)   (Show Source): You can put this solution on YOUR website!
.

In this problem, each ranking is a list of teams, ordered according to their ranks.

In other words, each ranking is some ordered list, or a permutation of 9 teams.

For 9 items/(teams), there are   9! = 9*8*7*6*5*4*3*2*1 = 362880 possible permutations/(rankings).     ANSWER

        Solved and explained.

----------------------

It is about PERMUTATIONS.

On Permutations, see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Simple and simplest problems on permutations
    - Special type permutations problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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