SOLUTION: A steel pipe 1 m in diameter is required to carry an internal pressure of 750 kPa, if the allowable tensile stress of steel is 140 MPa, determine the required thickness of the pipe

Question 1192376: A steel pipe 1 m in diameter is required to carry an internal pressure of 750 kPa, if the allowable tensile stress of steel is 140 MPa, determine the required thickness of the pipe in mm.
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
**1. Define Variables**
* **D:** Internal diameter of the pipe (1 meter = 1000 mm) = 1000 mm
* **t:** Required wall thickness (in mm)
* **P:** Internal pressure = 750 kPa = 750,000 Pa
* **σ:** Allowable tensile stress = 140 MPa = 140,000,000 Pa
**2. Apply the Barlow Formula**
* The Barlow formula for calculating the minimum required wall thickness of a cylindrical pressure vessel is:
t = (PD) / (2σ)
where:
* t = wall thickness
* P = internal pressure
* D = internal diameter
* σ = allowable tensile stress
**3. Calculate the Required Thickness**
* t = (750,000 Pa * 1000 mm) / (2 * 140,000,000 Pa)
* t = 750,000,000 / 280,000,000
* t = 2.6786 mm
**Therefore, the required thickness of the steel pipe is approximately 2.68 mm.**
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