SOLUTION: B. Magnitude of Vectors (Trigonometry) 2. Find the magnitude of the x- and y- components, to the nearest whole number if ||v|| = 29 units, and v has a direction angle of 25 degree

Question 1191443: B. Magnitude of Vectors (Trigonometry)
2. Find the magnitude of the x- and y- components, to the nearest whole number if ||v|| = 29 units, and v has a direction angle of 25 degrees.
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Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
Here's how to find the x and y components of the vector *v*:
* **Magnitude of v (||v||):** 29 units
* **Direction angle (θ):** 25 degrees
* **x-component (v_x):** ||v|| * cos(θ)
v_x = 29 * cos(25°)
v_x ≈ 29 * 0.9063
v_x ≈ 26.28
* **y-component (v_y):** ||v|| * sin(θ)
v_y = 29 * sin(25°)
v_y ≈ 29 * 0.4226
v_y ≈ 12.25
Rounding to the nearest whole number:
* **x-component:** 26 units
* **y-component:** 12 units

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