SOLUTION: Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0.

Question 1190935: Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
dy/dx=((2x-1)(x^2)'-x^2(2x-1)')/(2x-1)^2

point (0,0)
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
Find the coordinates of the points on the curve y = x^2/(2x-1) where dy/dx = 0.
~~~~~~~~~~~~~~~~~~

            In this problem, there are TWO points, satisfying the condition dy/dx=0.

            @josgarithmetic found one point and missed another.

            I came to bring full correct solution.

= ((2x-1)(x^2)'-x^2(2x-1)')/(2x-1)^2 = = = = 0 has two solutions x= 0 and x= 1. The two points on the curve with zero derivative are (x,y) = (0,0) and (x,y) = (1,1). ANSWER Visual illustration Plot y = (red) and y= 1 (horizontal tangent, green)

Solved (correctly).

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