SOLUTION: Draw on the same diagram,the graph of y =2 for x from -3 to 3 and graph of x = -2 for y from -3 to 3,Rotate the graph of y = 2 through 90° clockwise about the origin.State the equ

Question 1190480: Draw on the same diagram,the graph of y =2 for x from -3 to 3 and graph of x = -2 for y from -3 to 3,Rotate the graph of y = 2 through 90° clockwise about the origin.State the equation of the image line and Rotate the graph of x = -2 through 90° anticlockwise about the origin.State the equation of the image line.Write down the point of intersection of the two image lines
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
Unfortunately, I can't physically draw diagrams here. However, I can guide you through the process:
**1. Initial Graphs:**
* **y = 2:** This is a horizontal line passing through all points with a y-coordinate of 2. It would be a horizontal line segment from (-3, 2) to (3, 2).
* **x = -2:** This is a vertical line passing through all points with an x-coordinate of -2. It would be a vertical line segment from (-2, -3) to (-2, 3).
**2. Rotations:**
* **Rotating y = 2 clockwise 90° about the origin:** Imagine holding the y-axis as a pivot and rotating the line y = 2. It will become a vertical line passing through x = 2. So, the equation of the image line is **x = 2**.
* **Rotating x = -2 anticlockwise 90° about the origin:** Similarly, rotate the line x = -2 using the y-axis as a pivot. It will become a horizontal line passing through y = -2. The equation of the image line is **y = -2**.
**3. Point of Intersection:**
The two image lines, x = 2 and y = -2, intersect at the point **(2, -2)**.
**Summary:**
* Original lines: y = 2 and x = -2
* Image lines after rotation: x = 2 and y = -2
* Point of intersection of image lines: (2, -2)
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