SOLUTION: Solve 3cos(x+40°) = 4sin(x+40°) for 0° ≤ x ≤ 360°
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Question 1190279: Solve 3cos(x+40°) = 4sin(x+40°) for 0° ≤ x ≤ 360°
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
Solve for ° ≤ ≤ °
°
solutions:
°
for range ° ≤ ≤ °
radians:
degrees:
°
°
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Solve for ° ≤ ≤ °
~~~~~~~~~~~~~~~~~~~~~~
Below find the correct solution to replace the incorrect one from @MathLover1.
=
=
=
=
x = °
solutions:
x = °
for range ° ≤ ≤ °
= ° = 176.87°;
= ° = 356.87°.
ANSWER. Two solutions are 176.87° and 356.87° (both are approximate and rounded).
Solved.
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