SOLUTION: TRIGONOMETRY A. Find the exact solution to each equation for the interval 0°≤x<360°. 3. cosx = 2sinx 4. secx/1+secx = sec²x/2+secx <--(fraction form) (Show full soluti

Question 1189942: TRIGONOMETRY
A. Find the exact solution to each equation for the interval 0°≤x<360°.
3. cosx = 2sinx
4. secx/1+secx = sec²x/2+secx <--(fraction form)
(Show full solution)
Thank you! :)
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the exact solution to each equation for the interval 0°≤x<360°.
3. cosx = 2sinx
---------------------
cos^2(x) = 4sin^2(x)
1 - sin^2(x) = 4sin^2(x)
5sin^2(x) = 1
sin^2(x) = 1/5
sin(x) = sqrt(5)/5
x = ~ 29.517 degs
============
sin(x) = -sqrt(1/5)
x = ~ - 29.517 degs --- extraneous, ignore
----
Sine and cosine have the same sign, pos or negative, in Q1 and Q3.
Check for 29.517 + 180 degs
==================================
4. secx/1+secx = sec²x/2+secx <--(fraction form)
Ambiguous - add parentheses
Answer by MathLover1(20855) (Show Source): You can put this solution on YOUR website!

3.
given:
, in interval °≤<°
........both sides divide by

.....use identity

radians
°

Solutions for the range °≤<°:
radians

°
°

4.
.........cross multiply

.......simplify
..........simplify

}
°

Solutions for the range °≤<°:
Radians:

Degrees:
°
°
°
°

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