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Two buses leave a station at the same time and travel in opposite directions.
One bus travels 8kmh faster than the other. If the two buses are 976 kilometers apart
after 4 hours, what is the rate of each bus?
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Let x be the rate of the slower bus, in kilometers per hour.
Then the rate of the other bus is (x+8) km/h.
Write the total distance equation
4x + 4*(x+8) = 976.
Simplify and find x
4x + 4x + 32 = 976
8x = 976 - 32
8x = 944
x = 944/8 = 118.
ANSWER. The slower bus speed is 118 km/h. The faster bus speed is 118+8 = 126 km/h.
CHECK. 4*118 + 4*126 = 976 kilometers, total distance. ! Precisely correct !
Solved.
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For simple Travel & Distance problems, see introductory lessons
- Travel and Distance problems
- Travel and Distance problems for two bodies moving in opposite directions
- Travel and Distance problems for two bodies moving in the same direction (catching up)
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You will find the solutions of many similar problems there.
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