SOLUTION: A rectangular shaped mansion where the length was 12 more than the square of the width. If the perimeter of the mansion was 168 meters, what is the measure of its area? a. 1440

Question 1187427: A rectangular shaped mansion where the length was 12 more than the square of the width. If the perimeter of the mansion was 168 meters, what is the measure of its area?
a. 1440 sq. meters c. 1420 sq. meters
b. 1430 sq. meters d. 1410 sq. meters
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A rectangular shaped mansion where the length was 12 more than the square of the width. If the perimeter of the mansion was 168 meters, what is the measure of its area?
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P = 2W + 2L = 168
W + L = 84
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L = W^2 + 12
----
W^2 + 12 + W = 84
W^2 + W - 72 = 0
(W + 9)*(W- 8) = 0
W = 8
L = 76
Area = 608 sq meters

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

                        D U P L I C A T E

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https://www.algebra.com/algebra/homework/word/unit_conversion/Unit_Conversion_Word_Problems.faq.question.1187413.html

https://www.algebra.com/algebra/homework/word/unit_conversion/Unit_Conversion_Word_Problems.faq.question.1187413.html

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