SOLUTION: The first three terms of a geometric progression are k + 15,k and k - 12 respectively, find the value of k and the sum to infinity.

Algebra.Com
Question 1187235: The first three terms of a geometric progression are k + 15,k and k - 12 respectively, find the value of k and the sum to infinity.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
The first three terms of a geometric progression are k + 15,k and k - 12 respectively,
find the value of k and the sum to infinity.
~~~~~~~~~~~~~~

Since the first three terms of a geometric progression are k + 15,k and k - 12 respectively, 

we have this proportion


     = .


Cross multiply, simplify and find k


    (k-12)*(k+15) = k^2

     k^2 - 12k + 15k - 180 = k^2

           3k              = 180

            k              = 180/3 = 60.


The first three terms are  75, 60, 48.


The common dofference is  r =  =  = 0.8.


The sum to infinity is  S =  =  =  = 375.

Solved.



RELATED QUESTIONS

The first three terms of a geometric progression are k + 15,k and k - 12 respectively,... (answered by ikleyn)
If S is sum of infinite geometric series with first term k and common ratio is k/(k+1)... (answered by robertb)
The first three terms of an arithmetic progression are tan x, cos x, and sec x,... (answered by Aswathy)
The third term of a geometric progression is nine times the first term. The sum of the... (answered by ikleyn)
The third term of a geometric progression is nine times the first term.The sum of the... (answered by jim_thompson5910,ikleyn)
How to use the nth term of a geometric sequence to find the value of k. So the terms k-3, (answered by ikleyn)
The first term of an arithmetic progression is 12 and the sum of the first 16 terms is... (answered by greenestamps)
find the value of k so that 2k+2,5k-11,7k-13 is a geometric... (answered by Edwin McCravy)
The 3rd and the 4th terms of a geometric progression are 12 and 8 respectively. Find the... (answered by amfagge92)