SOLUTION: Obtain the first 4 terms in the expansion of (1+2x)^9 in ascending powers of x.Use this expansion to find an approximate value of (1.02)^9.

Question 1187141: Obtain the first 4 terms in the expansion of (1+2x)^9 in ascending powers of x.Use this expansion to find an approximate value of (1.02)^9.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the first term is 9C0(1^9)(2x)^0=1
the second term is 9C1*(1^8)(2x)^1=18x
the third term is 9C2*(1^7)*(2x)^2=36*4x^2=144x^2
the fourth term is 9C3*(1^6)(2x)^3=84*8x^3=672x^3
here, x=0.01
so the sum is 1+0.18+0.0144+0.000672=1.195072
1.195092 is the actual answer to 6 decimal places
RELATED QUESTIONS
Find,in ascending powers of x,the first 4 terms in the expansion of {{{(expr(1/2)x -... (answered by Edwin McCravy)

Obtain,in ascending powers of x,the first 4 terms in the expansion of (2-x/2)^7. Hence... (answered by greenestamps)

please help me on the following qn: Obtain the first four terms of the expansion of... (answered by Fombitz)

Use the expansion of (1+x)^n; to expand: 1/(1+7x)^4, in ascending powers of x, as far as... (answered by venugopalramana)

find in ascending powers of x the expansion of... (answered by MathLover1)

Find the coefficient of the fourth term in ascending powers of x in the expansion of (1... (answered by richwmiller)

a) Find in ascending powers of x the expansion of (2-x/2)^6 b) State the first three... (answered by Edwin McCravy)

Expand (1/4+2x) as a series of ascending powers of x up to the term x^3 and state the... (answered by robertb)

The coefficient of 5th 6th and 7th terms in the expansion ( 1+a)^7 in ascending powers of (answered by ikleyn)