.
Solve + = 16.
~~~~~~~~~~~~~~~~~~~
@MathLover1 solved ANOTHER equation, DIFFERENT from the given in the post.
So her solution and her answer have no any relation to the posed problem.
I came to bring the correct solution.
Your starting equation is
+ = 16.
Introduce new variable y = . Then the given equation takes the form
3y + = 16.
Multiply both sides by y. You will get an EQUIVALENT equation
3y^2 + 5 = 16y,
or
3y^2 - 16y + 5 = 0.
Apply the quadratic formula and find the roots. They are y = 5 and y = .
Hence, for x = , we have two values = 25 and = .
ANSWER. The given equation has two solutions x= 25 and/or x= .
You can easily check it by substituting these found values of x into the original equation.
Solved.