SOLUTION: Given that f(x) = 2x^2 - 8x + 1. Express 2x^2 - 8x + 1 in the form a(x+b)^2 + c,where a and b are integers. Find the coordinates of the stationary point on the graph of y = f(x).

Question 1184797: Given that f(x) = 2x^2 - 8x + 1. Express 2x^2 - 8x + 1 in the form a(x+b)^2 + c,where a and b are integers. Find the coordinates of the stationary point on the graph of y = f(x).
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

.........complete square

..........

vertex is at (,)
the stationary point on the graph:
The graph of a quadratic function (ie a parabola) only has a single stationary point.
For an ‘up’ parabola this is the minimum; for a ‘down’ parabola it is the maximum (no need to talk about ‘local’ here) The value of the stationary point is thus the or value of the quadratic function
so, the stationary point on the graph is (,)
or,
The specific nature of a stationary point at x can in some cases be determined by examining the second derivative '':
'
''

the stationary point on the graph is (,)

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