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In this problem, instead of 4 objects, we consider 4-1 = 3 objects,
looking at the pair SQ as one unit.
For 3 objects, we have 3! = 6 possible permutations;
therefore, the answer to the problem's question is 3! = 6.
Solved and explained.
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Hello, the previous solution was done assuming that speaker Q addresses IMMEDIATELY after speaker S.
If the problem means " after, but not necessary immediately after ", then the answer is = = 12:
In half of 4! = 24 permutations, Q follows S; in other half of permutations, S follows Q.