SOLUTION: The expression 6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.
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Question 1183386: The expression 6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.
Found 2 solutions by Solver92311, mananth:
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
If )
is divided by 
leaving a remainder of 
, then \ =\ \alpha)
So solve 
John
My calculator said it, I believe it, that settles it
From
I > Ø
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.
divisor = x-p
f(p) = 6p^2-2p+3
By remainder theorem f(p) =remainder= 3
2p(3p-1)=0
p= 0 or 1/3
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