SOLUTION: Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley so that the two masses hang freely. If initially the 9.0 kg mass is 4 meters fro

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Question 1182842: Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley so that the two masses hang freely. If initially the 9.0 kg mass is 4 meters from the floor, how long will it take this mass to reach the floor after the masses are released?

Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
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Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a smooth pulley
so that the two masses hang freely. If initially the 9.0 kg mass is 4 meters from the floor,
how long will it take this mass to reach the floor after the masses are released?
~~~~~~~~~~~~~~~~~~~


The acting force in the system is the "net force", which is equal to the difference of the masses' weights

    9*g - 6*g = 9*10 - 6*10 = 90 - 60 newtons = 30 newtons.


The total mass of the moving system is the SUM of the masses  6 kg + 9 kg = 15 kg.


THEREFORE, the acceleration of the masses is  a =  = 2 m/s^2,

according to the Newton's second law.



The time to reach the floor is  determined by the equation  for the uniformly accelerated body   = 4 meters;

from this equation,  t =  =  =  = 2 seconds.    ANSWER


Solved and carefully explained.



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