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The net force on a 2-kg body is 6 N. If the body is originally travelling with a velocity of 8 m/s,
and if the force applied is opposite to the velocity, find the distance it will move before coming to rest.
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We solve the problem and make calculations step by step.
(1) First we find the deceleration "a" by dividing the force by the mass (the second Newton's law)
a = = = 3 m/s^2.
(2) Next we find the time to get the zero speed from the basic kinematic equation
v = a*t,
where v is the initial velocity of 8 m/s (given) and "a" is the deceleration a = 3 m/s^2, found above in step (1)
t = = = 2.66666... seconds.
(3) Finally, we find the distance
d = = = = = 10 meters. ANSWER
Solved.