SOLUTION: Find a value of dy/dx at ( 1, 2) of the equation x2y3−7=ln(x+y−2)+1

SOLUTION: Find a value of dy/dx at ( 1, 2) of the equation x2y3−7=ln(x+y−2)+1

Algebra.Com

Question 1182253: Find a value of dy/dx at ( 1, 2) of the equation x2y3−7=ln(x+y−2)+1
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!




















Edwin

RELATED QUESTIONS
Given that dy/dx=a/x^2+1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)

Given that dy/dx=a/x^2 +1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)

I have a question regarding finding the second derivative of a hyperbola... Find the... (answered by Alan3354)

Find the value of {{{(dy)/(dx)}}} when x= -1 and y= 1, given that {{{3x^2+4xy-xy^3 =... (answered by ikleyn)

find dy/dx of... (answered by Alan3354)

Find dy/dx using the method of logarithmic differentiation when y = (4+9x^2)^ln(x)... (answered by Edwin McCravy)

If {{{y^2=1+sin x}}} and {{{y((d^2)y/d(x^2))+(dy/dx)^2+ay^2+b=0}}}, find the value of... (answered by robertb)

Given that dy/dx = 3x ^ 2 - 2/(x ^ 2) where x≠0 , and y = 5 when x=1, find the value (answered by ikleyn)

Find dy/dx of (3y^2/(1-3xy)) and find the point on the curve where dy/dx =... (answered by Edwin McCravy)