SOLUTION: The weekly sales s(x) of a product during an advertising campaign are given by
s(x) = 100x/(x^2 + 100).
where x is the number of weeks since the beginning of the campaign and s(x
Algebra.Com
Question 1182036: The weekly sales s(x) of a product during an advertising campaign are given by
s(x) = 100x/(x^2 + 100).
where x is the number of weeks since the beginning of the campaign and s(x) is in thousands of dollars.
a. Find the number of weeks, x for which weekly sales is maximized.
b. Prove that (a) is maximum.
c. What are the maximum weekly sales?
Answer by ikleyn(52914) (Show Source): You can put this solution on YOUR website!
.
It is a standard Calculus problem on finding the maximum/minimum.
Take the derivative of the function; equate it to zero;
from this equation find the value of x, which provides the maximum.
Then substitute this value of x into the function and calculate the maximum value.
Any Calculus student should be able to do it on his (or her) own.
If after my explanations you still have questions, do not hesitate to post them to me.
But your question should not be the same - "solve it for me . . . ".
It should show your work.
Happy calculations ( ! )
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