SOLUTION: The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 32 liters, and standard deviation of 9.5 liters. A) What is the probability that

Question 1179343: The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 32 liters, and standard deviation of 9.5 liters.
A) What is the probability that daily production is less than 35.9 liters? (Round your answer to 4 decimal places.)

B) What is the probability that daily production is more than 58.6 liters? (Round your answer to 4 decimal places.)
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!


Hi
Distribution: normal with µ = 32 and σ = 9.5
probability that daily production is:
Continuous Curve:
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus

P( x < 35.9) = P( x ≤ 35.9) =  normalcdf(-9999, 35.9,32,9.5) = .6593
Or
P( x >  58.6) = 1 - P( x ≤ 58.6) = 1 - normalcdf(-9999, 58.6,32,9.5) = 1-.9974 = .0026
Wish You the Best in your Studies.

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