SOLUTION: five points O,A,B,C,D are taken in order on a straight line with distances OA=a, OB=b,OC=c,and OD=d. P is a point on the line between B and C and such that AP:PD=BP:PC. Find OP

Question 1178381: five points O,A,B,C,D are taken in order on a straight line with distances OA=a, OB=b,OC=c,and OD=d.
P is a point on the line between B and C and such that AP:PD=BP:PC.
Find OP in terms of a,b,c,d.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Let BP=x. Then

AP = b+x
PD = d-(b+x)
BP = x
PC = c-(b+x)

AP/PD = (b+x)/(d-(b+x))

BP/PC = x/(c-(b+x))

AP/PD = BP/PC:

ANSWER:

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