SOLUTION: The number of solutions (x,y) of the equation ,3x+y=100, where x and y are positive integers, is

Question 1178308: The number of solutions (x,y) of the equation ,3x+y=100, where x and y are positive integers, is
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52800) (Show Source): You can put this solution on YOUR website!
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Use any of the values x = 1, 2, 3, . . . , 33 and the corresponding value of y = 100 - 33x. Doing this way, you will get your answer 33 for the number of solutions.

Solved, answered and explained.

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Solving the given equation for y gives

y = 100-3x

Since 100 and 3x are both positive integers, y will also be a positive integer, as long as 3x is less than 100.

So as tutor @ikleyn says in her response, x can be any positive integer less than 100/3.

That gives us 33 solutions to the given equation with x and y both positive integers.

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