You can
put this solution on YOUR website!solve: (n)/(n-3) + n=(7n-18)/(n-3)
Multiply thru by (n-3) to get:
n + n(n-3) = 7n-18
n + n^2 - 3n = 7n - 18
n^2 -9n +18 = 0
(n-6)(n-3) = 0
n = 6
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n cannot be 3 because that would make the
denominator of the original prolem be zero.
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Cheers,
Stan H.