The force of attraction (F) between two opposite electric charges varies inversely as the square of the distance (d) between them.
Let's pause here.
For all proportion problems, start with this:
Varying "directly" or product of "jointlys" or 1 if none
quantity = k ∙ ----------------------------------------------------------
inversely variable or product of "inverselys" or 1 if none
In this problem the varying quantity is F. There are no "directly" or "jointly"
variable. So the numerator is the number 1. We have one inversely, d2. So we
have F on the left, 1 on the top of the fraction and d2 on the bottom:
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If F = 30 newtons when d = 5 meters,
Let's pause again here.
Let's substitute 30 for F in , and 5 for d2>/sub>, and solve for k:
Put 1 under 30 and write 52 as 25:
Cross-multiply:
Now we substitute 750 for k in
find F when d = 12 meters.
newtons.
Edwin