SOLUTION: The concentration of the active ingredient in capsules of a prescription painkiller varies according to
a normal distribution with μ = 10% and σ = 0.2%.
a. What is the median c
Algebra.Com
Question 1170316: The concentration of the active ingredient in capsules of a prescription painkiller varies according to
a normal distribution with μ = 10% and σ = 0.2%.
a. What is the median concentration? Explain your answer.
b. What interval of concentrations covers the middle 95 percent of all the capsules?
c. What interval covers the middle half of all capsules?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The median is the same as the mean in a normal distribution, so Md=10%
95% is +/-1.96 sd from the mean included
that is +/-0.392 or 0.4 (9.6%, 10.4%) rounding
-
Middle half is +/- 0.2500 probability from the mean.
This is z=+/-0.675 or 0.135%
the interval is (9.865%, 10.135%)
RELATED QUESTIONS
A pharmacist is to prepare 18 milliliters of special eye drops for a glaucoma patient.... (answered by edjones)
How much water needs to be added to a half ounce of a solution in which the active... (answered by stanbon)
A pharmacist is to prepare 20 ml of a special eye drop for a glaucoma patient the eye... (answered by Alan3354)
A pharmacist is to prepare 20 ml of a special eye drop for a glaucoma patient the eye... (answered by Alan3354)
A pharmacist is to prepare 20 ml of a special eye drop for a glaucoma patient the eye... (answered by Alan3354)
A pharmacist is to prepare 20 ml of a special eye drop for a glaucoma patient the eye... (answered by Alan3354)
A pharmacist is to prepare 20 ml of a special eye drop for a glaucoma patient the eye... (answered by Alan3354)
A pharmacist is to prepare 18 milliliters of special eye drops for a
glaucoma patient. (answered by josmiceli)
A pharmacist is to prepare 15 milliliters of special eye drops for a glaucoma patient.... (answered by ewatrrr)