SOLUTION: 2log(x+2)-log(x+5)=log2+log(x-2)
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Question 1167514: 2log(x+2)-log(x+5)=log2+log(x-2)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The difference of the logs is the log of the quotient.
The sum of the logs is the log of the product.
\ =\ \log\(x^n\))
\ -\ \log(x\,+\,5)\ =\ \log(2)\ +\ \log(x\,-\,2))
^2}{x\,+\,5}\)\ =\ \log(2x\,-\,4))
\ =\ \log(b)\ \Leftrightarrow\ a\ =\ b)
^2}{x\,+\,5}\ =\ 2x\,-\,4)
Solve the quadratic. One of the roots will be extraneous (gives a negative argument for a couple of the log functions)
John
My calculator said it, I believe it, that settles it
I > Ø
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