SOLUTION: Hi there! Help would be super appreciated. This is for Calculus homework, but idk which category this would fit under.
Calculate y' and y" at the point (1,1) on the curve 3xy^
Algebra.Com
Question 1166986: Hi there! Help would be super appreciated. This is for Calculus homework, but idk which category this would fit under.
Calculate y' and y" at the point (1,1) on the curve 3xy^2+2y-3=2.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Implicit differentiation, presuming 
is a function of 
}{dy}\cdot\frac{dy}{dx}\ +\ \frac{d(3x)}{dx}\cdot y^2\ +\ \frac{d(2y)}{dy}\cdot\frac{dy}{dx}\ -\ \frac{d(3)}{dx}\ =\ \frac{d(2)}{dx})
\ =\ -3y^2)
}\ =\ \frac{3}{8})
For the 
part you need to implicitly differentiate 
with respect to . You will need the Quotient Rule, the Product Rule, and the Chain Rule. Good luck and have fun.
John
My calculator said it, I believe it, that settles it
I > Ø
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