.
Tutor Theo misread the problem, so his solution is conceptually incorrect.
I came to guide you in right direction.
The area of the garden is 15*20 = 30 square meters;
so the area inside the fence is 2*300 = 600 square meters.
Thus this part is solved: it is easy part.
Now let start working on the second question.
Lex x be the uniform distance around the flower bed.
Then the dimensions of the fence are (15+2x) meters width and (20+2x) meters length.
The area inside the fence is then (15+2x)*(20+2x).
From here you have this equation to determine x
(15+2x)*(20+2x) = 2*15*20 = 600.
Reduce this equation to the standard quadratic equation form and solve using the quadratic formula.
4x^2 + 70x - 300 = 0.
It has no solution/solutions in integer or rational numbers, so other solution methods (guessing or factoring)
do not work.
When you find the value of x, you determine the perimeters as
(15+2x) + (20+2x) + (15+2x) + 20+2x).
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To see many other similar solved problems (your potential TEMPLATES), look into the lessons
- Problems on the area and the dimensions of a rectangle surrounded by a strip
- Cynthia Besch wants to buy a rug for a room
- Problems on a circular pool and a walkway around it
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic
"Dimensions and the area of rectangles and circles and their elements".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.