SOLUTION: It took Jim 25 minutes to ride to the bicycle shop and 1 hour and 15 min to walk home. If he can ride his bike 8 km/hr faster than he can walk, how far is the repair shop? Thank

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Question 1165976: It took Jim 25 minutes to ride to the bicycle shop and 1 hour and 15 min to walk home. If he can ride his bike 8 km/hr faster than he can walk, how far is the repair shop?
Thank you!
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
15 minutes is hour.
25 minutes is hour. 
             SPEED          TIME          DISTANCE
RIDE TO        r+8                  d
WALK Back      r                   d

This is not the only way, but the distances d being equal each way,

Solve this for r, and then evaluate .
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
It took Jim 25 minutes to ride to the bicycle shop and 1 hour and 15 min to walk home.
If he can ride his bike 8 km/hr faster than he can walk, how far is the repair shop?
~~~~~~~~~~~~~~ 


Another way to solve the problem is to notice that 1 hour and 15 minutes is  75 minutes

and the ratio of traveled times is   = 3.


It means that the rate cycling is 3 times the rate walking,

So, the rate cycling is 3x, where x is the rate walking.


But the difference of the rates is

    3x - x = 8 km/h,   or

    2x     = 8 km/h,

     x     = 8/2 = 4 km/h.


So, to find the distance, multiply the rate walking, or 4 km/h, by the time walking, which is 1 hour and 15 minutes, ot   hours.
You will get then the distance =  = 5 kilometers.    ANSWER

Solved.



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