SOLUTION: Please help me out: Integer whose square are less than 200 but greater than 40?

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Question 1163378: Please help me out: Integer whose square are less than 200 but greater than 40?
Found 3 solutions by math_helper, ikleyn, MathTherapy:
Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!


You can guess the solutions pretty easily:
not a solution
not a solution
is a solution
is a solution
...
etc.
Keep increasing the integer value until its square is 200 or higher.

Keep in mind the "integers" include the addititive inverses (negative numbers) and for n<0. Thus, -7, -8, etc. will also be in the set of solutions.
Answer by ikleyn(52852)   (Show Source): You can put this solution on YOUR website!
.

To the list,  presented by tutor  @MathTherapy,  add the numbers  +/- 14.



Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Please help me out: Integer whose square are less than 200 but greater than 40?
Let INTEGERS be I

Then we get: 40 < I2 < 200

 <  <  ------ Taking square root of each component of compound inequality, while ADDING ±

 < I <  

Integers, or  

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