SOLUTION: Determine the equation of the tangent to the curve f(x) = (2x^2 - 1)^-5 at x = 1. Leave your final answer at standard form.
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Question 1163275: Determine the equation of the tangent to the curve f(x) = (2x^2 - 1)^-5 at x = 1. Leave your final answer at standard form.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Find the coordinates of the point of tangency:
\)\|_{x=1}\ =\ \(1,\,(2(1)^2\,-\,1\)^{-5}\)\ =\ \(1,\,(1)^{-5}\)\ =\ (1,1))
Let )
, then 
, then
^{-6}\(4x\))
Then
^{-6}\(4(x)\)\ =\ -24)
So write a linear equation that represents a line that goes through the point (1,1) with a slope of -24.
John
My calculator said it, I believe it, that settles it
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