SOLUTION: Which set of values for x should be tested to determine the possible zeros of
x^3 - 2x^2 + 3x - 12
a) 1, 2, 3, 4, 6, and 12
b) ±2, ±3, ±4, ±6, and ±12
c) ±1, ±2, ±3
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Question 1161511: Which set of values for x should be tested to determine the possible zeros of
x^3 - 2x^2 + 3x - 12
a) 1, 2, 3, 4, 6, and 12
b) ±2, ±3, ±4, ±6, and ±12
c) ±1, ±2, ±3, ±4, and ±6
d) ±1, ±2, ±3, ±4, ±6, and ±12
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39799) (Show Source): You can put this solution on YOUR website!
Review the Rational Roots Theorem.
Choice (d).
Answer by ikleyn(53763) (Show Source): You can put this solution on YOUR website!
.
All the divisors of the constant term -12 should be tested, each with the " + " and the " - " sign.
+/-1, +/-2, +/-3, +/-4, +/-6, +/-12.
Option d) in your list.
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