SOLUTION: factor fully, 3x^3 - 2x^2-7x - 2 a) (3x+1)(x-7)(x+2) b) (3x-1)(x-2)((x-1) c) (3x-1)(x+2)(x+1) d) (3x+1)(x-2)(x+1)

Question 1161508: factor fully,
3x^3 - 2x^2-7x - 2
a) (3x+1)(x-7)(x+2)
b) (3x-1)(x-2)((x-1)
c) (3x-1)(x+2)(x+1)
d) (3x+1)(x-2)(x+1)
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

You can try to regroup to look for a factorization.

You can also try synthetic division for root checking. (Related to using Rational Roots Theorem)

Check for root, -1 for factor x+1, gives quotient 3x^2-5x-2.
Checking that for root,2 for factor x-2, gives quotient 3x+1.

FACTORIZATION:
FACTORIZATION:
Pick the correct choice. You know the commutative property for multiplication.
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