SOLUTION: Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to its resting place, the cheetah travels an average of
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Question 1161417: Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to its resting place, the cheetah travels an average of 70 mph. If the cheetah traveled for 15 minutes, how many minutes did the return trip take to the nearest minute and second?
a. Set up the table as follows. Label the rows “To the River” and “From the River.” Label the columns “Distance,” “Rate,” and “Time (in Hours).” Let t represent the unknown quantity in the problem. Fill in the table.
b. From the table, set up an equation relating the distances.
c. Solve the problem. Write the answer in a complete sentence, stating it in terms of minutes and seconds.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x hours to go to the river
0.25-x hours to come back, since 15 minutes is 0.25 hr.
to the river 40 mph * x hours =40x miles
from the river 70 mph (0.25-x) hours=17.5-70x
those two are equal
40x=17.5-70x
110x=17.5
x=17.5/110=0.159 hours
9.55 minutes
0.25-x=0.091 hours=5.46 minutes (rounding) on the return, which is the answer.
5.46 minutes (actually 5.457) is 27.42 seconds, so it is 5 min 27.4 seconds. If it is done without rounding until the end, the answer is 5 min 27.2727 repeat seconds, but to the nearest second it is 5m27s, as above.
The river happens to be 6.36 miles away
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