SOLUTION: y=x^2+6x+3 What is the axis of symmetry? x=x= Compute the coordinates of the vertex: (( , )) compute the yy-intercept as a point: (( , )) find the point symmetric to the yy-interce
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Question 1159758: y=x^2+6x+3 What is the axis of symmetry? x=x= Compute the coordinates of the vertex: (( , )) compute the yy-intercept as a point: (( , )) find the point symmetric to the yy-intercept
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
Put the equation in vertex form:
In that form, the vertex is at (h,k), and the axis of symmetry is x=h.
Complete the square....
This form of the equation tells us that the vertex is at (-3,-6) and the axis of symmetry is x=-3. That can be seen in the graph:
For the y-intercept, set x=0 and evaluate. Using the given form of the equation, it is easy to see that the y-intercept is (0,3).
The y-intercept is 3 units to the right of the axis of symmetry; the point symmetric with the y-intercept will be 3 units to the left of the axis of symmetry, and it will have the same y value as the y-intercept: (-6,3). That is also easily seen in the graph.
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