SOLUTION: Consider the parabola y=x2−6x+4. What is the axis of symmetry? x= Compute the coordinates of the vertex: ( , ) compute the y-intercept as a point: ( , ) find the po

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Question 1159743: Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the point symmetric to the y-intercept:

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
Consider the parabola

What is the axis of symmetry?
The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
so, write your equation in vertex form:
....complete square
......


-> and , so x -coordinate of the vertex is



Compute the coordinates of the vertex: done above
(,)

compute the y-intercept as a point:
y-intercept where


(,)
find the point symmetric to the y-intercept
axis of symmetry is , so axis is three units to the right from the y-intercept, and the point symmetric to the y-intercept will be three more units to the right from axis at:
(,)


Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: (
,
)
compute the y-intercept as a point: (
,
)
find the point symmetric to the y-intercept:

Axis of symmetry:
y-coordinate of vertex:
Coordinates of the vertex:
Substitute 0 for x in the equation, and compute to get the y-intercept!
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