SOLUTION: Find the equation of the line tangent to the following curve at the given value of x. y = cos(2x); x = π/8
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Question 1158628: Find the equation of the line tangent to the following curve at the given value of x. y = cos(2x); x = π/8
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ \cos(2x))
\ =\ -2\sin(2x))
Evaluate:
)
Which is the 
-coordinate of the function at 
)
Which is the slope of the tangent line at
Now, using the point-slope form of an equation of a line, write the desired equation:
\)\ =\ \(y'\(\frac{\pi}{8}\)\)\(x\ -\ \frac{\pi}{8}\))
You can do the appropriate calculations and simplifications for yourself.
John
My calculator said it, I believe it, that settles it
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