SOLUTION: When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when the expression is divided by (x+1). Show that c can have any value and find b in terms of
Algebra.Com
Question 1157973: When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when the expression is divided by (x+1). Show that c can have any value and find b in terms of a.
Answer by KMST(5377) (Show Source): You can put this solution on YOUR website!
If you divide by , you obtain a quotient and remainder that is a constant.
You may remember that in then
If you did not remember, you would understand that if the reminder is ,
it means that and that
for , .
So --> .
Similarly the remainder, when dividing by is
--> .
Then, -->-->-->-->
RELATED QUESTIONS
When ax³ + bx² + cx - 4 is divided by (x+2), the remainder is double that obtained when (answered by MathLover1)
Please help me solve this question:-
1.) When polynomial ax^3+bx^2+cx-4 is divided by... (answered by stanbon)
The expression x^3 + ax^2 + bx + 3 is exactly divisible by x+3 but it leaves a remainder... (answered by ikleyn)
The remainder when ax^3 + bx^2 + 2x + 3 is divided by x-1 is twice that when it is... (answered by robertb)
The expression ax²+bx+c is divisible by (x-1),has remainder 2 when divided by (x+1) and... (answered by Boreal)
The expression x^4 + ax^3 + 5x^2 + bx + 6 when divide by (x-2), the remainder is 16 and... (answered by solver91311)
When f(x)= ax^2+bx-4 is divided by x+2, the remainder is -2. When f(x) is divided by x+3, (answered by josgarithmetic)
the remainders when f(x)=x³+ax²+bx+c is divided by (x-1),(x+2) and (x-2) are respectively (answered by ikleyn)
when the expression x^4+ax^3+5x^2+bx+6 is divided by(x-2), the remainder is 16. when it... (answered by josgarithmetic)